Ok, Sorry my Title is misleading but I cannot edit it, so if a moderator can do I would appreciate that, not my good Ist starting post !
Title should have been “My 486 machine won’t boot up , Dos 6.2 and Win 3.1”
thanks in advance for trying to help me, I have an old engraving machine that runs on Dos, and also some engraving related software that runs under win 3.1, and once I finish planning my job or project, using this engraving software running under win3.1, this engraving software then allows me to save my job files as well as export the job file to another program where that is imported and runs my engraving machine, I had a job where I needed to scan a logo that needed engraving, so i got my scanner out and tried configuring it to this engraving software, ( like selecting printers for example, so i had to tell this engraving software what scanner i was using and already its drivers were loaded in the windows 3.1, only that this engraving software had to be configured to allow that scanner to scan image and input its tiff or twain data into this software, so whilst i was trying to do this, my computer froze, and had to be forced shut down, and now it won’t boot up again not even in dos, since it always booted in Dos first, from where it comes up with a page that allowed me to choose if I want to boot up in Dos or in windows, but I am not even able to get to this far before I can ask it to boot in dos or in windows, the screen remains dead, no nothing, and I tried a few on/off attempts, it may suddenly boot up but most times it does not, so i also tried inserting any random floppy disc, it then starts to boot up and comes up with a message like not a system boot disc, please remove disc and try again, so when I remove disc, it then continues to boot up from main C drive and that is how I can still use it, but this is not how it used to be, has my registry file been altered and gone corrupted? if so how do I get to correct it?
Yes, if you can try your monitor on another computer (or another monitor on this one) it would be good to eliminate it from the equation.
Always pop back and let us know the outcome – thanks