I want to convert date passed as a variable in the format
'DD-MON-YY' i.e., '31-JUL-08' to 'YYYYMMDD' format
'20080731' . Someone gimme a single line command. Anybody here, help...!

TIA

TIA
Covina

If someone can post from the otherway, it's fine with me, i.e., convert from 'YYYYMMDD' to 'DD-MON-YY'.

TIA
Covina

You'll never do this in one line because of having to convert the year string to a number:

#!/bin/ksh
# This korn shell function receives a date of the format
# 01-AUG-08 and returns a string YYYYMMDD
function yrmmdd
{
typeset -2Z mm
typeset -2Z yr
# parse the argument into $1, $2, $3
set - $(IFS="-"; echo $1)
yr=$3
dd=$1
case $2 in
   "JAN") mm=1;;
   "FEB") mm=2;;
   "MAR") mm=3;;
   "APR") mm=4;;
   "MAY") mm=5;;
   "JUN") mm=6;;
   "JUL") mm=7;;
   "AUG") mm=8;;
   "SEP") mm=9;;
   "OCT") mm=10;;
   "NOV") mm=11;;
   "DEC") mm=12;;
   *)  echo "error"
       exit ;;
esac
echo "20"${yr}${mm}${dd}
} # end function

dstr=01-AUG-08
retstr=$(yrmmdd $dstr)
echo $retstr

In fact, I answered a similar question for you here:

http://www.computing.net/answers/un...

Using ksh93, I can be done as a one-liner.

$ printf "%(%Y%m%d)T\n" "31-JUL-2008"
20080731