Solved Comparing Decimal Number’s In Unix Shell Script

Since the version i.e.11.5.70 is not a valid number, I think you’ll have to break each file’s version number into 3 tuplets and compare each one. It’s a kludge, but here is one way to do it:

#!/bin/ksh

file1="11.5.69"
file2="1.5.70"

# break file1 into $1, $2, $3
set $(IFS="."; echo $file1)
f11=$1
f12=$2
f13=$3

# break file2 into $1, $2, $3
set $(IFS="."; echo $file2)

while true
do

   if [ $1 -eq $f11 ]
   then
      :
   else
      if [ $1 -gt $f11 ]
      then
         echo "File2 is greater"
      else
         echo "File1 is greater"
      fi
      break
   fi

   if [ $2 -eq $f12 ]
   then
      :
   else
      if [ $2 -gt $f12 ]
      then
         echo "File2 is greater"
      else
         echo "File1 is greater"
      fi
      break
   fi

   if [ $3 -eq $f13 ]
   then
      echo "files are equal"
   else
      if [ $3 -gt $f13 ]
      then
         echo "File2 is greater"
      else
         echo "File1 is greater"
      fi
   fi

   break
done
# end script

Of course, the limitation is that each version has to be 3 tuplets.

Second:

I am not familiar with the command adident, so I cannot comment on that. However, you can also get the version from the included string using awk; it’s the 3rd field:

echo ” $Header: OEXVHLSB.pls 115.10 2002/12/05 18:38:07 ” |awk ‘ { print $3 } ‘

You can also get the date and time string; it’s the 4th and 5th fields:

echo ” $Header: OEXVHLSB.pls 115.10 2002/12/05 18:38:07 ” |awk ‘ { print $4 $5 }
‘
Including a datetime comparison is not simple; IMO, it involves changing the datetime to the number of seconds since the unix epoch, Jan 1, 1970, which isn’t easy using classic unix tools (i.e. non-GNU tools). To perform epoch calculations, I use perl. Here is an example post:

https://computing.net/answers/pr…

Date conversion has been discussed a lot on computing.net. Perform this google for many examples:

site:computing.net epoch